As shown in the diagram,overline{ OA } and ov | vedclass

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(D) The shaded region is the area of the quadrant $OAB$ minus the area of the triangle $OD A$.
Given radius $r = 21 	ext{ cm}$.
Area of quadrant $O

Vedclass · Accepted Answer

$241.5$

Vedclass · Answer

(D) The shaded region is the area of the quadrant $OAB$ minus the area of the triangle $OD A$.
Given radius $r = 21 	ext{ cm}$.
Area of quadrant $OAB = \frac{1}{4} \pi r^2 = \frac{1}{4} 	imes \frac{22}{7} 	imes 21 	imes 21 = \frac{1}{4} 	imes 22 	imes 3 	imes 21 = \frac{1386}{4} = 346.5 	ext{ cm}^2$.
Area of $	riangle ODA = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes OD 	imes OA = \frac{1}{2} 	imes 10 	imes 21 = 105 	ext{ cm}^2$.
Area of shaded region = Area of quadrant $OAB - 	ext{Area of } 	riangle ODA = 346.5 - 105 = 241.5 	ext{ cm}^2$.

As shown in the diagram,$\overline{ OA }$ and $\overline{ OB }$ are two radii of $\odot( O , 21 \text{ cm} )$ perpendicular to each other. If $OD = 10 \text{ cm}$,find the area of the shaded region. (in $\text{cm}^2$)

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